- Home
- Standard 11
- Chemistry
p-Block Elements - I
normal
Consider the following statements for diborane
$1.$ Boron is approximately $sp^3$ hybridized
$2.$ $B-H-B$ angle is $180^o$
$3.$ There are two terminal $B-H$ bonds for each boron atom
$4.$ There are only $12$ bonding electrons available
Of these statements
A
$1,\, 3$ and $4$ are correct
B
$1,\, 2$ and $3$ are correct
C
$2,\, 3$ and $4$ are correct
D
$1,\, 2$ and $4$ are correct
Solution
In diborane, boron atom undergoes sp $^{3}$ hybridization.
In diborane, the $\mathrm{B}-\mathrm{H}-\mathrm{B}$ angle is $83^{\circ}$.
Each boron atom is linked to two terminal hydrogen atoms and two bridged hydrogen atoms. There are four $2 \mathrm{c}-2 \mathrm{e}$ bonds and two $3 \mathrm{c}-2 \mathrm{e}$ bonds.
Hence, only 12 bonding electrons are available
Standard 11
Chemistry
